本帖最后由 lazygc520 于 2013-09-05 13:13:44 编辑 已知数组a和数组b
<br />$a = array (<br /> 0 => <br /> array (<br /> 'cust_no' => '310F6 1VA5A',<br /> 'lotno' => '2X15',<br /> 'count' => '0',<br /> ),<br /> 1 => <br /> array (<br /> 'cust_no' => '310F6 1VA5A',<br /> 'lotno' => '2Z15',<br /> 'count' => '16',<br /> ),<br />);<br /><br />$b = array (<br /> 0 => <br /> array (<br /> 'cust_no' => '310F6 1VA5A',<br /> 'lotno' => '2X15',<br /> 'count' => '0',<br /> ),<br /> 1 => <br /> array (<br /> 'cust_no' => '310F6 1VA5A',<br /> 'lotno' => '2Z15',<br /> 'count' => '32',<br /> ),<br /> 2 => <br /> array (<br /> 'cust_no' => '310F6 1VA5A',<br /> 'lotno' => '3528',<br /> 'count' => '80',<br /> ),<br />);<br />
想要得到的结果是当数组b和数组a的cust_no和lotno都相同时,则提示update table sql
否则insert table sql。请问怎么求?