取出本周的周一和周日的时间戳

<script>ec(2);</script>

方法一
echo strtotime('last Monday');
echo '
';
echo strtotime('next Sunday');
?>

方法二
 

02 function getMonSun(){ 

03     $curTime=time(); 

04         

05     $curWeekday = date('w'); 

06   

07      //为0是 就是 星期七 

08     $curWeekday = $curWeekday?$curWeekday:7; 

09   

10   

11     $curMon = $curTime - ($curWeekday-1)*86400; 

12     $curSun = $curTime + (7 - $curWeekday)*86400; 

13        

14     $cur['Mon'] = $curMon; 

15     $cur['Sun'] = $curSun; 

16   

17     return $cur; 

18 } 

19     $cur = getMonSun(); 

20   

21     echo date('Y-m-d',$cur['Mon']); 

22     echo "rn"; 

23     echo date('Y-m-d',$cur['Sun']); 

24 ?>

方法三

 

02 function getMonSun(){ 

03      $curTime=time(); 

04         

05      //求出当前是星期几： 

06      $curWeekday = date('w'); 

07         

08      //如果是周一则减上7*86400周二减上6*86400，依此类推得到周一的时间戳： 

09      switch ($curWeekday) { 

10      case 0: 

11      $curMon = $curTime-7*86400; 

12          $curSun = $curTime; 

13      break; 

14      case 1: 

15      $curMon = $curTime; 

16           $curSun = $curTime+6*86400; 

17      break; 

18      case 2: 

19      $curMon = $curTime-1*86400; 

20          $curSun = $curTime+5*86400; 

21      break; 

22      case 3: 

23      $curMon = $curTime-2*86400; 

24          $curSun = $curTime+4*86400; 

25      break; 

26      case 4: 

27      $curMon = $curTime-3*86400; 

28          $curSun = $curTime+3*86400; 

29      break; 

30      case 5: 

31      $curMon = $curTime-4*86400; 

32          $curSun = $curTime+2*86400; 

33      break; 

34      case 6: 

35      $curMon = $curTime-5*86400; 

36          $curSun = $curTime+1*86400; 

37      break; 

38     } 

39     $cur['Mon'] = $curMon; 

40     $cur['Sun'] = $curSun; 

41   

42     return $cur; 

43 } 

44 $cur = getMonSun(); 

45          echo date('Y-m-d',$cur['Mon']); 

46          echo "rn"; 

47      echo date('Y-m-d',$cur['Sun']); 

48 ?>