关于Select Where In 的排序问题

有很多人不知道SQL里怎么按 Select Where In 的内容进行字段排序.假如SQL语句为:

代码如下:
Select *
FROM table1
Where (ID IN (3,5,1,4,2))

代码如下:
Select *
FROM table1
Where (ID IN (3,5,1,4,2))如果In后面的条件都是数字,那MSSQL排序应该为


代码如下:
Select *
FROM table1
Where (ID IN (3,5,1,4,2))
orDER BY CHARINDEX(',' + CONVERT(nvarchar, ID) + ',', ',' + CONVERT(nvarchar, Replace('3,5,1,4,2', ' ','')) + ',')

代码如下:
Select *
FROM table1
Where (ID IN (3,5,1,4,2))
orDER BY CHARINDEX(',' + CONVERT(nvarchar, ID) + ',', ',' + CONVERT(nvarchar, Replace('3,5,1,4,2', ' ','')) + ',')改进方法,不去处理空格,直接改用空格判断.可以用来判断少数有空格的字符条件.

代码如下:
Select *
FROM table1
Where (ID IN (3,5,1,4,2))
orDER BY PATINDEX('% ' + CONVERT(nvarchar(4000), ID) + ' %', ' ' + CONVERT(nvarchar(4000), Replace('3,5,1,4,2', ',',' , ')) + ' ')

代码如下:
Select *
FROM table1
Where (ID IN (3,5,1,4,2))
orDER BY PATINDEX('% ' + CONVERT(nvarchar(4000), ID) + ' %', ' ' + CONVERT(nvarchar(4000), Replace('3,5,1,4,2', ',',' , ')) + ' ')

其实还是在SQL外处理好条件字符串再进行查询和排序比较好.
对于MYSQL排序可能要改为(MYSQL不熟):

代码如下:
Select *
FROM table1
Where (ID IN (3,5,1,4,2))
orDER BY FIND_IN_SET(ID, '3,5,1,4,2')