


Method: 1. Use the perl command, the syntax is "find -name'file name'|xargs perl-pi-e 's|Original content|New content|g'"; 2. Use the sed command, The syntax is "sed-i "s/original content/new content/g" `grep original content-rl directory`".
#The operating environment of this tutorial: linux7.3 system, Dell G3 computer.
How to batch replace file contents in Linux
Method 1
Use perl, the command is as follows:
find -name '要查找的文件名' | xargs perl -pi -e 's|被替换的字符串|替换后的字符串|g'
The following example is to Replace ”http://repo1.maven.org/maven2“ in all pom.xml files in the current directory and all subdirectories with ”http://localhost:8081/nexus/content /groups/public“.
find -name 'pom.xml' | xargs perl -pi -e 's|http://repo1.maven.org/maven2|http://localhost:8081/nexus/content /groups/public|g'
The Perl language is used here,
perl -pi -e Add the -e option to the Perl command, followed by a line of code, then it will Run this code like a normal Perl script.
Using Perl from the command line can help achieve some powerful, real-time transformations. Studying regular expressions carefully and using them correctly will save you a lot of manual editing work.
find -name 'pom.xml' | xargs perl -pi -e 's|http://repo1.maven.org/maven2|http://localhost:8081/nexus/content/groups/public|g'
Method 2
Use the sed command as follows:
sed -i "s/原字符串/新字符串/g" `grep 原字符串 -rl 所在目录`
A simple method to batch replace strings in multiple files under Linux. Use the sed command to batch replace strings in multiple files.
For example: I want to replace mahuinan with huinanma, execute the command:
sed -i "s/mahuinan/huinanma/g" 'grep mahuinan -rl /www'
This is currently the simplest batch replacement string command in Linux!
The specific format is as follows:
sed -i "s/oldString/newString/g" `grep oldString -rl /path`
Example code:
sed -i "s/大小多少/日月水火/g" `grep 大小多少 -rl /usr/aa` sed -i "s/大小多少/日月水火/g" `grep 大小多少 -rl ./`
Related recommendations: "Linux Video Tutorial"
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