Java does not have unsigned numbers, which can cause a lot of problems.
static byte[] x = {(byte) 0xff,(byte) 0xff};
public static void main(String[] args) throws IOException {
byte a = x[0];
int z = a&0xff;
System.out.println(z);
}int z = a&0xff,
First of all, a is of byte type. When performing & operation on it, it will be converted to int type first, that is,
1111 1111 1111 1111 1111 1111 1111 1111
&
0000 0000 0000 0000 0000 0000 1111 1111
=0000 0000 0000 0000 0000 0000 1111 1111
The result is 255. If the &0xff operation is not performed and assigned directly to z, the obtained value is -1.
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