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php实现用于验证所有类型的信用卡类

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2016-06-13 09:09:591240browse

php实现用于验证所有类型的信用卡类

 这篇文章主要介绍了php实现用于验证所有类型的信用卡类,实例分析了信用卡类的实现原理与相关使用技巧,具有一定参考借鉴价值,需要的朋友可以参考下

 

 

本文实例讲述了php实现用于验证所有类型的信用卡类。分享给大家供大家参考。具体如下:

这个php类比较完整,可以用于验证各种不同的信用卡,针对信用卡的卡号的通用规则进行了验证,同时对不同类型的信用卡进行了针对性的识别。
代码接受一个信用卡号码和有效日期,如果两者都有效,则返回TRUE,否则返回FALSE。

本插件接受以下参数:
$number 表示信用卡号码的一个字符串
$expiry 信用卡有效日期,采用07/12或0712这样的格式

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// Plug-in 32: Validate Credit Card

// This is an executable example with additional code supplied

// To obtain just the plug-ins please click on the Download link

$card = "4567 1234 5678 9101";

$exp = "06/11";

echo "Validating: $card : $exp
";

$result = PIPHP_ValidateCC($card, $exp);

if ($result != FALSE) echo "Card Validated";

else echo "Card did not validate";

function PIPHP_ValidateCC($number, $expiry)

{

// Plug-in 32: Validate Credit Card

//

// This plug-in accepts a credit card number and

// an expiry date and returns TRUE or FALSE,

// depending on whether the details pass date

// and checksum validation. The arguments required

// are:

//

// $number: Credit Card Number

// $expiry: Expiry date in the form:

// 07/12 or 0712 (for July, 2012)

$number = preg_replace('/[^\d]/', '', $number);

$expiry = preg_replace('/[^\d]/', '', $expiry);

$left = substr($number, 0, 4);

$cclen = strlen($number);

$chksum = 0;

// Diners Club

if (($left >= 3000) && ($left

($left >= 3600) && ($left

($left >= 3800) && ($left

if ($cclen != 14) return FALSE;

// JCB

if (($left >= 3088) && ($left

($left >= 3096) && ($left

($left >= 3112) && ($left

($left >= 3158) && ($left

($left >= 3337) && ($left

($left >= 3528) && ($left

if ($cclen != 16) return FALSE;

// American Express

elseif (($left >= 3400) && ($left

($left >= 3700) && ($left

if ($cclen != 15) return FALSE;

// Carte Blanche

elseif (($left >= 3890) && ($left

if ($cclen != 14) return FALSE;

// Visa

elseif (($left >= 4000) && ($left

if ($cclen != 13 && $cclen != 16) return FALSE;

// MasterCard

elseif (($left >= 5100) && ($left

if ($cclen != 16) return FALSE;

// Australian BankCard

elseif ($left == 5610)

if ($cclen != 16) return FALSE;

// Discover

elseif ($left == 6011)

if ($cclen != 16) return FALSE;

// Unknown

else return FALSE;

for ($j = 1 - ($cclen % 2); $j

$chksum += substr($number, $j, 1);

for ($j = $cclen % 2; $j

{

$d = substr($number, $j, 1) * 2;

$chksum += $d

}

if ($chksum % 10 != 0) return FALSE;

if (mktime(0, 0, 0, substr($expiry, 0, 2), date("t"),

substr($expiry, 2, 2))

return TRUE;

}

?>

希望本文所述对大家的php程序设计有所帮助。

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