php实现用于验证所有类型的信用卡类
这篇文章主要介绍了php实现用于验证所有类型的信用卡类,实例分析了信用卡类的实现原理与相关使用技巧,具有一定参考借鉴价值,需要的朋友可以参考下
本文实例讲述了php实现用于验证所有类型的信用卡类。分享给大家供大家参考。具体如下:
这个php类比较完整,可以用于验证各种不同的信用卡,针对信用卡的卡号的通用规则进行了验证,同时对不同类型的信用卡进行了针对性的识别。
代码接受一个信用卡号码和有效日期,如果两者都有效,则返回TRUE,否则返回FALSE。
本插件接受以下参数:
$number 表示信用卡号码的一个字符串
$expiry 信用卡有效日期,采用07/12或0712这样的格式
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// Plug-in 32: Validate Credit Card // This is an executable example with additional code supplied // To obtain just the plug-ins please click on the Download link $card = "4567 1234 5678 9101"; $exp = "06/11"; echo "Validating: $card : $exp $result = PIPHP_ValidateCC($card, $exp); if ($result != FALSE) echo "Card Validated"; else echo "Card did not validate"; function PIPHP_ValidateCC($number, $expiry) { // Plug-in 32: Validate Credit Card // // This plug-in accepts a credit card number and // an expiry date and returns TRUE or FALSE, // depending on whether the details pass date // and checksum validation. The arguments required // are: // // $number: Credit Card Number // $expiry: Expiry date in the form: // 07/12 or 0712 (for July, 2012) $number = preg_replace('/[^\d]/', '', $number); $expiry = preg_replace('/[^\d]/', '', $expiry); $left = substr($number, 0, 4); $cclen = strlen($number); $chksum = 0; // Diners Club if (($left >= 3000) && ($left ($left >= 3600) && ($left ($left >= 3800) && ($left if ($cclen != 14) return FALSE; // JCB if (($left >= 3088) && ($left ($left >= 3096) && ($left ($left >= 3112) && ($left ($left >= 3158) && ($left ($left >= 3337) && ($left ($left >= 3528) && ($left if ($cclen != 16) return FALSE; // American Express elseif (($left >= 3400) && ($left ($left >= 3700) && ($left if ($cclen != 15) return FALSE; // Carte Blanche elseif (($left >= 3890) && ($left if ($cclen != 14) return FALSE; // Visa elseif (($left >= 4000) && ($left if ($cclen != 13 && $cclen != 16) return FALSE; // MasterCard elseif (($left >= 5100) && ($left if ($cclen != 16) return FALSE; // Australian BankCard elseif ($left == 5610) if ($cclen != 16) return FALSE; // Discover elseif ($left == 6011) if ($cclen != 16) return FALSE; // Unknown else return FALSE; for ($j = 1 - ($cclen % 2); $j $chksum += substr($number, $j, 1); for ($j = $cclen % 2; $j { $d = substr($number, $j, 1) * 2; $chksum += $d } if ($chksum % 10 != 0) return FALSE; if (mktime(0, 0, 0, substr($expiry, 0, 2), date("t"), substr($expiry, 2, 2)) return TRUE; } ?> |
希望本文所述对大家的php程序设计有所帮助。

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