PHP stripos
stripos() 函数返回字符串在另一个字符串中第一次出现的位置。与strpos(),stripos()不区分大小写
string 必需。规定被搜索的字符串。
find 必需。规定要查找的字符。
start 可选。规定开始搜索的位置。
$findme = 'a';
$mystring1 = 'xyz';
$mystring2 = 'ABC';
$pos1 = stripos($mystring1, $findme);
$pos2 = stripos($mystring2, $findme);
// Nope, 'a' is certainly not in 'xyz'
if ($pos1 === false) {
echo "The string '$findme' was not found in the string '$mystring1'";
}
// Note our use of ===. Simply == would not work as expected
// because the position of 'a' is the 0th (first) character.
if ($pos2 !== false) {
echo "We found '$findme' in '$mystring2' at position $pos2";
}
?>
strpos() - 查找的字符串的第一个出现的位置
strrpos() - 查找字符串中的字符的最后出现的位置
strrchr() - 查找字符串中的字符最后一次出现
substr() - 返回字符串的一部分
stristr() - 忽略大小写strstr
strstr() - 查找第一次出现的字符串
strripos() - 找出案件的最后出现的位置在一个字符串不敏感的字符串
str_ireplace() - 病例的str_replace区分版本。

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