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PHP 怎么执行mongodb 的 $in 和$size查询

原创
2016-10-17 09:30:22 1413浏览

假设有个这样的集合

<code>{ "_id" : ObjectId("5022518d09248743250688e0"), "name" : "big fruit", "fruits" : [ "apple", "pear", "orange" ] } , 
{ "_id" : ObjectId("502251a309248743250688e1"), "name" : "good fruit", "fruits" : [ "banana", "pear", "orange" ] }  ,
{ "_id" : ObjectId("502251c109248743250688e2"), "name" : "good fruit", "fruits" : [ "banana", "apple", "tomato" ] }  </code>

假设有这样的集合

RT 者两句代码用PHP怎么写

<code>db.coll.find({_id:{$in[ ObjectId("502251a309248743250688e1"), ObjectId("502251c109248743250688e2")]}})</code>

查询长度为三的数组

<code>db.coll.find({fruits:{$size:0}})</code>

用PHP的话要怎么实现

回复内容:

假设有个这样的集合

<code>{ "_id" : ObjectId("5022518d09248743250688e0"), "name" : "big fruit", "fruits" : [ "apple", "pear", "orange" ] } , 
{ "_id" : ObjectId("502251a309248743250688e1"), "name" : "good fruit", "fruits" : [ "banana", "pear", "orange" ] }  ,
{ "_id" : ObjectId("502251c109248743250688e2"), "name" : "good fruit", "fruits" : [ "banana", "apple", "tomato" ] }  </code>

假设有这样的集合

RT 者两句代码用PHP怎么写

<code>db.coll.find({_id:{$in[ ObjectId("502251a309248743250688e1"), ObjectId("502251c109248743250688e2")]}})</code>

查询长度为三的数组

<code>db.coll.find({fruits:{$size:0}})</code>

用PHP的话要怎么实现

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